(4x+1)(4x-1)=16x^2-1

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Solution for (4x+1)(4x-1)=16x^2-1 equation: 



(4x+1)(4x-1)=16x^2-1

We move all terms to the left:

(4x+1)(4x-1)-(16x^2-1)=0

We use the square of the difference formula

16x^2-(16x^2-1)-1=0

We get rid of parentheses

16x^2-16x^2+1-1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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